freebsd-drivers

Hi,

I need to defer part of my interrupt handler to a kernel thread and am 
currently doing this by using my own thread based on taskqueue(9) (via 
taskqueue_create_fast -> taskqueue_start_threads)

My original support target where FreeBSD 6.3 and newer but now I need to 
support the entire 6 branch and in 6.0 taskqueue_start_threads does not 
exist.

So, in taskqueue(9) for BSD6.0 the following is written:
>>>
The thread queue can be used, for instance, by interrupt level routines
that need to call kernel functions that do things that can only be done
from a thread context.  (e.g., call malloc with the M_WAITOK flag.)
<<<
This is excellent. To conserve resources I can use the predefined 
[taskqueue_thread] symbol and enqueue on that in my interrupt handler, 
instead of reverting to kthreads.

But how?

taskqueue_thread is at boot constructed as an MTX_DEF mutex and 6.0 
taskqueue_enqueue does not detect the type of mutex for the passed 
taskqueue pointer, so I must use taskqueue_enqueue_fast, which obviously 
does not work on taskqueue_thread. (Can't go mtx_lock_spin() on 
MTX_DEFs, and can't go use mtx_lock() from within an interrupt context)

How am I supposed to implement that above snippet from within my 
interrupt context handler?

Thanx,
/Phil
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